[LeetCode] 1693. Daily Leads and Partners
[문제] [MySQL]WITH Unique_leads AS ( SELECT date_id , make_name , COUNT(DISTINCT lead_id) AS unique_leads FROM DailySales GROUP BY date_id, make_name) , Unique_partners AS ( SELECT date_id , make_name , COUNT(DISTINCT partner_id) AS unique_partners FROM DailySales GROUP BY date_id, make_name)SELECT ul.* , up.unique_partnersFROM Unique_leads AS ul ..