[HackerRank] Top Competitors

 

 

[문제]

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[MySQL]

SELECT h.hacker_id
     , h.name
FROM Submissions AS s
    LEFT JOIN Hackers AS h ON h.hacker_id = s.hacker_id
    LEFT JOIN Challenges AS c ON s.challenge_id = c.challenge_id
    LEFT JOIN Difficulty AS d ON c.difficulty_level = d.difficulty_level
WHERE d.score = s.score
GROUP BY h.hacker_id, h.name
HAVING COUNT(h.hacker_id) > 1
ORDER BY COUNT(h.hacker_id) DESC, h.hacker_id ASC